Optimal. Leaf size=61 \[ \frac{a c^2 \tan ^3(e+f x)}{3 f}+\frac{a c^2 \tanh ^{-1}(\sin (e+f x))}{2 f}-\frac{a c^2 \tan (e+f x) \sec (e+f x)}{2 f} \]
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Rubi [A] time = 0.104285, antiderivative size = 61, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 5, integrand size = 30, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.167, Rules used = {3958, 2611, 3770, 2607, 30} \[ \frac{a c^2 \tan ^3(e+f x)}{3 f}+\frac{a c^2 \tanh ^{-1}(\sin (e+f x))}{2 f}-\frac{a c^2 \tan (e+f x) \sec (e+f x)}{2 f} \]
Antiderivative was successfully verified.
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Rule 3958
Rule 2611
Rule 3770
Rule 2607
Rule 30
Rubi steps
\begin{align*} \int \sec (e+f x) (a+a \sec (e+f x)) (c-c \sec (e+f x))^2 \, dx &=-\left ((a c) \int \left (c \sec (e+f x) \tan ^2(e+f x)-c \sec ^2(e+f x) \tan ^2(e+f x)\right ) \, dx\right )\\ &=-\left (\left (a c^2\right ) \int \sec (e+f x) \tan ^2(e+f x) \, dx\right )+\left (a c^2\right ) \int \sec ^2(e+f x) \tan ^2(e+f x) \, dx\\ &=-\frac{a c^2 \sec (e+f x) \tan (e+f x)}{2 f}+\frac{1}{2} \left (a c^2\right ) \int \sec (e+f x) \, dx+\frac{\left (a c^2\right ) \operatorname{Subst}\left (\int x^2 \, dx,x,\tan (e+f x)\right )}{f}\\ &=\frac{a c^2 \tanh ^{-1}(\sin (e+f x))}{2 f}-\frac{a c^2 \sec (e+f x) \tan (e+f x)}{2 f}+\frac{a c^2 \tan ^3(e+f x)}{3 f}\\ \end{align*}
Mathematica [B] time = 0.717691, size = 313, normalized size = 5.13 \[ -\frac{a c^2 \sec (e) \sec ^3(e+f x) \left (-12 \sin (2 e+f x)+6 \sin (e+2 f x)+6 \sin (3 e+2 f x)+4 \sin (2 e+3 f x)+3 \cos (2 e+3 f x) \log \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )+3 \cos (4 e+3 f x) \log \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )+9 \cos (f x) \left (\log \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )\right )+9 \cos (2 e+f x) \left (\log \left (\cos \left (\frac{1}{2} (e+f x)\right )-\sin \left (\frac{1}{2} (e+f x)\right )\right )-\log \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )\right )-3 \cos (2 e+3 f x) \log \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )-3 \cos (4 e+3 f x) \log \left (\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )\right )\right )}{48 f} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.022, size = 84, normalized size = 1.4 \begin{align*} -{\frac{{c}^{2}a\sec \left ( fx+e \right ) \tan \left ( fx+e \right ) }{2\,f}}+{\frac{{c}^{2}a\ln \left ( \sec \left ( fx+e \right ) +\tan \left ( fx+e \right ) \right ) }{2\,f}}-{\frac{{c}^{2}a\tan \left ( fx+e \right ) }{3\,f}}+{\frac{{c}^{2}a\tan \left ( fx+e \right ) \left ( \sec \left ( fx+e \right ) \right ) ^{2}}{3\,f}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 0.966504, size = 146, normalized size = 2.39 \begin{align*} \frac{4 \,{\left (\tan \left (f x + e\right )^{3} + 3 \, \tan \left (f x + e\right )\right )} a c^{2} + 3 \, a c^{2}{\left (\frac{2 \, \sin \left (f x + e\right )}{\sin \left (f x + e\right )^{2} - 1} - \log \left (\sin \left (f x + e\right ) + 1\right ) + \log \left (\sin \left (f x + e\right ) - 1\right )\right )} + 12 \, a c^{2} \log \left (\sec \left (f x + e\right ) + \tan \left (f x + e\right )\right ) - 12 \, a c^{2} \tan \left (f x + e\right )}{12 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 0.482892, size = 263, normalized size = 4.31 \begin{align*} \frac{3 \, a c^{2} \cos \left (f x + e\right )^{3} \log \left (\sin \left (f x + e\right ) + 1\right ) - 3 \, a c^{2} \cos \left (f x + e\right )^{3} \log \left (-\sin \left (f x + e\right ) + 1\right ) - 2 \,{\left (2 \, a c^{2} \cos \left (f x + e\right )^{2} + 3 \, a c^{2} \cos \left (f x + e\right ) - 2 \, a c^{2}\right )} \sin \left (f x + e\right )}{12 \, f \cos \left (f x + e\right )^{3}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} a c^{2} \left (\int \sec{\left (e + f x \right )}\, dx + \int - \sec ^{2}{\left (e + f x \right )}\, dx + \int - \sec ^{3}{\left (e + f x \right )}\, dx + \int \sec ^{4}{\left (e + f x \right )}\, dx\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 1.54994, size = 158, normalized size = 2.59 \begin{align*} \frac{3 \, a c^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) + 1 \right |}\right ) - 3 \, a c^{2} \log \left ({\left | \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right ) - 1 \right |}\right ) - \frac{2 \,{\left (3 \, a c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{5} + 8 \, a c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{3} - 3 \, a c^{2} \tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )\right )}}{{\left (\tan \left (\frac{1}{2} \, f x + \frac{1}{2} \, e\right )^{2} - 1\right )}^{3}}}{6 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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